Solve x-9x+20divx^2+x-20

$$x-9x+20 \div { x }^{ 2 } +x-20$$

Evaluate

$$-7x-20+\frac{20}{x^{2}}$$

Short Solution Steps

Combine x and -9x to get -8x.

$$-8x+\frac{20}{x^{2}}+x-20$$

Combine -8x and x to get -7x.

$$-7x+\frac{20}{x^{2}}-20$$

To add or subtract expressions, expand them to make their denominators the same. Multiply -7x-20 times \frac{x^{2}}{x^{2}}.

$$\frac{\left(-7x-20\right)x^{2}}{x^{2}}+\frac{20}{x^{2}}$$

Since \frac{\left(-7x-20\right)x^{2}}{x^{2}} and \frac{20}{x^{2}} have the same denominator, add them by adding their numerators.

$$\frac{\left(-7x-20\right)x^{2}+20}{x^{2}}$$

Do the multiplications in \left(-7x-20\right)x^{2}+20.

$$\frac{-7x^{3}-20x^{2}+20}{x^{2}}$$

Factor

$$-\frac{7x^{3}+20x^{2}-20}{x^{2}}$$