Solve x-4+2x+182+x+4+1x+255

$$x-4+2x+182+x+4+1x+255$$

Evaluate

$$5x+437$$

Solution Steps

Combine x and 2x to get 3x.

$$3x-4+182+x+4+1x+255$$

Add -4 and 182 to get 178.

$$3x+178+x+4+1x+255$$

Combine 3x and x to get 4x.

$$4x+178+4+1x+255$$

Add 178 and 4 to get 182.

$$4x+182+1x+255$$

Combine 4x and 1x to get 5x.

$$5x+182+255$$

Add 182 and 255 to get 437.

$$5x+437$$

Differentiate w.r.t. x

$$5$$

Steps Using Derivative Rule for Sum

Combine x and 2x to get 3x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x-4+182+x+4+1x+255)$$

Add -4 and 182 to get 178.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x+178+x+4+1x+255)$$

Combine 3x and x to get 4x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(4x+178+4+1x+255)$$

Add 178 and 4 to get 182.

$$\frac{\mathrm{d}}{\mathrm{d}x}(4x+182+1x+255)$$

Combine 4x and 1x to get 5x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(5x+182+255)$$

Add 182 and 255 to get 437.

$$\frac{\mathrm{d}}{\mathrm{d}x}(5x+437)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$5x^{1-1}$$

Subtract 1 from 1.

$$5x^{0}$$

For any term t except 0, t^{0}=1.

$$5\times 1$$

For any term t, t\times 1=t and 1t=t.

$$5$$