Solve for x
x=3\left(y+1\right)
Solve for y
y=\frac{x-3}{3}
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x-3=3y
Add 3y to both sides. Anything plus zero gives itself.
x=3y+3
Add 3 to both sides.
-3y-3=-x
Subtract x from both sides. Anything subtracted from zero gives its negation.
-3y=-x+3
Add 3 to both sides.
-3y=3-x
The equation is in standard form.
\frac{-3y}{-3}=\frac{3-x}{-3}
Divide both sides by -3.
y=\frac{3-x}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{x}{3}-1
Divide -x+3 by -3.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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