Solve x-3x-3/x^2-9=

$$x-3 \frac{ x-3 }{ { x }^{ 2 } -9 } =$$

Evaluate

$$\frac{x^{2}+3x-3}{x+3}$$

Short Solution Steps

Factor the expressions that are not already factored in \frac{x-3}{x^{2}-9}.

$$x-3\times \frac{x-3}{\left(x-3\right)\left(x+3\right)}$$

Cancel out x-3 in both numerator and denominator.

$$x-3\times \frac{1}{x+3}$$

Express 3\times \frac{1}{x+3} as a single fraction.

$$x-\frac{3}{x+3}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply x times \frac{x+3}{x+3}.

$$\frac{x\left(x+3\right)}{x+3}-\frac{3}{x+3}$$

Since \frac{x\left(x+3\right)}{x+3} and \frac{3}{x+3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{x\left(x+3\right)-3}{x+3}$$

Do the multiplications in x\left(x+3\right)-3.

$$\frac{x^{2}+3x-3}{x+3}$$

Expand

$$\frac{x^{2}+3x-3}{x+3}$$

Short Solution Steps

Factor the expressions that are not already factored in \frac{x-3}{x^{2}-9}.

$$x-3\times \frac{x-3}{\left(x-3\right)\left(x+3\right)}$$

Cancel out x-3 in both numerator and denominator.

$$x-3\times \frac{1}{x+3}$$

Express 3\times \frac{1}{x+3} as a single fraction.

$$x-\frac{3}{x+3}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply x times \frac{x+3}{x+3}.

$$\frac{x\left(x+3\right)}{x+3}-\frac{3}{x+3}$$

Since \frac{x\left(x+3\right)}{x+3} and \frac{3}{x+3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{x\left(x+3\right)-3}{x+3}$$

Do the multiplications in x\left(x+3\right)-3.

$$\frac{x^{2}+3x-3}{x+3}$$