Solve x-20geq2left(x+4-20right)

$$x-20 \geq 2 \left( x+4-20 \right)$$

Solve for x

$$x\leq 12$$

Solution Steps

Subtract 20 from 4 to get -16.

$$x-20\geq 2\left(x-16\right)$$

Use the distributive property to multiply 2 by x-16.

$$x-20\geq 2x-32$$

Subtract 2x from both sides.

$$x-20-2x\geq -32$$

Combine x and -2x to get -x.

$$-x-20\geq -32$$

Add 20 to both sides.

$$-x\geq -32+20$$

Add -32 and 20 to get -12.

$$-x\geq -12$$

Divide both sides by -1. Since -1 is negative, the inequality direction is changed.

$$x\leq \frac{-12}{-1}$$

Fraction \frac{-12}{-1} can be simplified to 12 by removing the negative sign from both the numerator and the denominator.

$$x\leq 12$$