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x-2\sqrt{x}=3
Add 3 to both sides. Anything plus zero gives itself.
-2\sqrt{x}=3-x
Subtract x from both sides of the equation.
\left(-2\sqrt{x}\right)^{2}=\left(3-x\right)^{2}
Square both sides of the equation.
\left(-2\right)^{2}\left(\sqrt{x}\right)^{2}=\left(3-x\right)^{2}
Expand \left(-2\sqrt{x}\right)^{2}.
4\left(\sqrt{x}\right)^{2}=\left(3-x\right)^{2}
Calculate -2 to the power of 2 and get 4.
4x=\left(3-x\right)^{2}
Calculate \sqrt{x} to the power of 2 and get x.
4x=9-6x+x^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(3-x\right)^{2}.
4x+6x=9+x^{2}
Add 6x to both sides.
10x=9+x^{2}
Combine 4x and 6x to get 10x.
10x-x^{2}=9
Subtract x^{2} from both sides.
10x-x^{2}-9=0
Subtract 9 from both sides.
-x^{2}+10x-9=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=10 ab=-\left(-9\right)=9
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as -x^{2}+ax+bx-9. To find a and b, set up a system to be solved.
1,9 3,3
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 9.
1+9=10 3+3=6
Calculate the sum for each pair.
a=9 b=1
The solution is the pair that gives sum 10.
\left(-x^{2}+9x\right)+\left(x-9\right)
Rewrite -x^{2}+10x-9 as \left(-x^{2}+9x\right)+\left(x-9\right).
-x\left(x-9\right)+x-9
Factor out -x in -x^{2}+9x.
\left(x-9\right)\left(-x+1\right)
Factor out common term x-9 by using distributive property.
x=9 x=1
To find equation solutions, solve x-9=0 and -x+1=0.
9-2\sqrt{9}-3=0
Substitute 9 for x in the equation x-2\sqrt{x}-3=0.
0=0
Simplify. The value x=9 satisfies the equation.
1-2\sqrt{1}-3=0
Substitute 1 for x in the equation x-2\sqrt{x}-3=0.
-4=0
Simplify. The value x=1 does not satisfy the equation.
x=9
Equation -2\sqrt{x}=3-x has a unique solution.