Solve x-12+x+x+110

$$x-12+x+x+110$$

Evaluate

$$3x+98$$

Solution Steps

Combine x and x to get 2x.

$$2x-12+x+110$$

Combine 2x and x to get 3x.

$$3x-12+110$$

Add -12 and 110 to get 98.

$$3x+98$$

Differentiate w.r.t. x

$$3$$

Steps Using Derivative Rule for Sum

Combine x and x to get 2x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x-12+x+110)$$

Combine 2x and x to get 3x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x-12+110)$$

Add -12 and 110 to get 98.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x+98)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$3x^{1-1}$$

Subtract 1 from 1.

$$3x^{0}$$

For any term t except 0, t^{0}=1.

$$3\times 1$$

For any term t, t\times 1=t and 1t=t.

$$3$$