Solve x-(405-x)div1.1=27

$$x-(405-x) \div 1.1=27$$

Solve for x

$$x=207$$

Steps for Solving Linear Equation

Divide each term of 405-x by 1.1 to get \frac{405}{1.1}+\frac{-x}{1.1}.

$$x-\left(\frac{405}{1.1}+\frac{-x}{1.1}\right)=27$$

Expand \frac{405}{1.1} by multiplying both numerator and the denominator by 10.

$$x-\left(\frac{4050}{11}+\frac{-x}{1.1}\right)=27$$

Divide -x by 1.1 to get -\frac{10}{11}x.

$$x-\left(\frac{4050}{11}-\frac{10}{11}x\right)=27$$

To find the opposite of \frac{4050}{11}-\frac{10}{11}x, find the opposite of each term.

$$x-\frac{4050}{11}-\left(-\frac{10}{11}x\right)=27$$

The opposite of -\frac{10}{11}x is \frac{10}{11}x.

$$x-\frac{4050}{11}+\frac{10}{11}x=27$$

Combine x and \frac{10}{11}x to get \frac{21}{11}x.

$$\frac{21}{11}x-\frac{4050}{11}=27$$

Add \frac{4050}{11} to both sides.

$$\frac{21}{11}x=27+\frac{4050}{11}$$

Convert 27 to fraction \frac{297}{11}.

$$\frac{21}{11}x=\frac{297}{11}+\frac{4050}{11}$$

Since \frac{297}{11} and \frac{4050}{11} have the same denominator, add them by adding their numerators.

$$\frac{21}{11}x=\frac{297+4050}{11}$$

Add 297 and 4050 to get 4347.

$$\frac{21}{11}x=\frac{4347}{11}$$

Divide both sides by \frac{21}{11}.

$$x=\frac{\frac{4347}{11}}{\frac{21}{11}}$$

Express \frac{\frac{4347}{11}}{\frac{21}{11}} as a single fraction.

$$x=\frac{4347}{11\times \frac{21}{11}}$$

Multiply 11 and \frac{21}{11} to get 21.

$$x=\frac{4347}{21}$$

Divide 4347 by 21 to get 207.

$$x=207$$