Solve x=4div1-4div2+4div3-4div4+4div5-4div6+4div7

$$x=4 \div 1-4 \div 2+4 \div 3-4 \div 4+4 \div 5-4 \div 6+4 \div 7$$

Solve for x

$$x = \frac{319}{105} = 3\frac{4}{105} \approx 3.038095238$$

Steps for Solving Linear Equation

Anything divided by one gives itself.

$$x=4-\frac{4}{2}+\frac{4}{3}-\frac{4}{4}+\frac{4}{5}-\frac{4}{6}+\frac{4}{7}$$

Divide 4 by 2 to get 2.

$$x=4-2+\frac{4}{3}-\frac{4}{4}+\frac{4}{5}-\frac{4}{6}+\frac{4}{7}$$

Subtract 2 from 4 to get 2.

$$x=2+\frac{4}{3}-\frac{4}{4}+\frac{4}{5}-\frac{4}{6}+\frac{4}{7}$$

Convert 2 to fraction \frac{6}{3}.

$$x=\frac{6}{3}+\frac{4}{3}-\frac{4}{4}+\frac{4}{5}-\frac{4}{6}+\frac{4}{7}$$

Since \frac{6}{3} and \frac{4}{3} have the same denominator, add them by adding their numerators.

$$x=\frac{6+4}{3}-\frac{4}{4}+\frac{4}{5}-\frac{4}{6}+\frac{4}{7}$$

Add 6 and 4 to get 10.

$$x=\frac{10}{3}-\frac{4}{4}+\frac{4}{5}-\frac{4}{6}+\frac{4}{7}$$

Divide 4 by 4 to get 1.

$$x=\frac{10}{3}-1+\frac{4}{5}-\frac{4}{6}+\frac{4}{7}$$

Convert 1 to fraction \frac{3}{3}.

$$x=\frac{10}{3}-\frac{3}{3}+\frac{4}{5}-\frac{4}{6}+\frac{4}{7}$$

Since \frac{10}{3} and \frac{3}{3} have the same denominator, subtract them by subtracting their numerators.

$$x=\frac{10-3}{3}+\frac{4}{5}-\frac{4}{6}+\frac{4}{7}$$

Subtract 3 from 10 to get 7.

$$x=\frac{7}{3}+\frac{4}{5}-\frac{4}{6}+\frac{4}{7}$$

Least common multiple of 3 and 5 is 15. Convert \frac{7}{3} and \frac{4}{5} to fractions with denominator 15.

$$x=\frac{35}{15}+\frac{12}{15}-\frac{4}{6}+\frac{4}{7}$$

Since \frac{35}{15} and \frac{12}{15} have the same denominator, add them by adding their numerators.

$$x=\frac{35+12}{15}-\frac{4}{6}+\frac{4}{7}$$

Add 35 and 12 to get 47.

$$x=\frac{47}{15}-\frac{4}{6}+\frac{4}{7}$$

Reduce the fraction \frac{4}{6} to lowest terms by extracting and canceling out 2.

$$x=\frac{47}{15}-\frac{2}{3}+\frac{4}{7}$$

Least common multiple of 15 and 3 is 15. Convert \frac{47}{15} and \frac{2}{3} to fractions with denominator 15.

$$x=\frac{47}{15}-\frac{10}{15}+\frac{4}{7}$$

Since \frac{47}{15} and \frac{10}{15} have the same denominator, subtract them by subtracting their numerators.

$$x=\frac{47-10}{15}+\frac{4}{7}$$

Subtract 10 from 47 to get 37.

$$x=\frac{37}{15}+\frac{4}{7}$$

Least common multiple of 15 and 7 is 105. Convert \frac{37}{15} and \frac{4}{7} to fractions with denominator 105.

$$x=\frac{259}{105}+\frac{60}{105}$$

Since \frac{259}{105} and \frac{60}{105} have the same denominator, add them by adding their numerators.

$$x=\frac{259+60}{105}$$

Add 259 and 60 to get 319.

$$x=\frac{319}{105}$$

Assign x

$$x≔\frac{319}{105}$$