Solve for x
x=2\left(y-4\right)^{2}
Solve for y
y=-\frac{\sqrt{2x}}{2}+4
y=\frac{\sqrt{2x}}{2}+4\text{, }x\geq 0
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x=2\left(y^{2}-8y+16\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(y-4\right)^{2}.
x=2y^{2}-16y+32
Use the distributive property to multiply 2 by y^{2}-8y+16.
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