Solve x=((2*y+31+(z/4))*50)div100

$$x=((2 \times y+31+( \frac{ z }{ 4 } )) \times 50) \div 100$$

Solve for x

$$x=\frac{z}{8}+y+\frac{31}{2}$$

Solution Steps

Use the distributive property to multiply 2y+31+\frac{z}{4} by 50.

$$x=\frac{100y+1550+50\times \frac{z}{4}}{100}$$

Express 50\times \frac{z}{4} as a single fraction.

$$x=\frac{100y+1550+\frac{50z}{4}}{100}$$

Divide 50z by 4 to get \frac{25}{2}z.

$$x=\frac{100y+1550+\frac{25}{2}z}{100}$$

Divide each term of 100y+1550+\frac{25}{2}z by 100 to get y+\frac{31}{2}+\frac{1}{8}z.

$$x=y+\frac{31}{2}+\frac{1}{8}z$$

Solve for y

$$y=-\frac{z}{8}+x-\frac{31}{2}$$

Solution Steps

Use the distributive property to multiply 2y+31+\frac{z}{4} by 50.

$$x=\frac{100y+1550+50\times \frac{z}{4}}{100}$$

Express 50\times \frac{z}{4} as a single fraction.

$$x=\frac{100y+1550+\frac{50z}{4}}{100}$$

Divide 50z by 4 to get \frac{25}{2}z.

$$x=\frac{100y+1550+\frac{25}{2}z}{100}$$

Divide each term of 100y+1550+\frac{25}{2}z by 100 to get y+\frac{31}{2}+\frac{1}{8}z.

$$x=y+\frac{31}{2}+\frac{1}{8}z$$

Swap sides so that all variable terms are on the left hand side.

$$y+\frac{31}{2}+\frac{1}{8}z=x$$

Subtract \frac{31}{2} from both sides.

$$y+\frac{1}{8}z=x-\frac{31}{2}$$

Subtract \frac{1}{8}z from both sides.

$$y=x-\frac{31}{2}-\frac{1}{8}z$$