Solve for x
x = \frac{118}{39} = 3\frac{1}{39} \approx 3.025641026
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x≔\frac{118}{39}
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x=\frac{8+\frac{14}{13}}{3}
The opposite of -\frac{14}{13} is \frac{14}{13}.
x=\frac{\frac{104}{13}+\frac{14}{13}}{3}
Convert 8 to fraction \frac{104}{13}.
x=\frac{\frac{104+14}{13}}{3}
Since \frac{104}{13} and \frac{14}{13} have the same denominator, add them by adding their numerators.
x=\frac{\frac{118}{13}}{3}
Add 104 and 14 to get 118.
x=\frac{118}{13\times 3}
Express \frac{\frac{118}{13}}{3} as a single fraction.
x=\frac{118}{39}
Multiply 13 and 3 to get 39.
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