Solve x=40n+2/n+3

$$x= \frac{ 40n+2 }{ n+3 }$$

Solve for n

$$n=-\frac{3x-2}{x-40}$$

$$x\neq 40$$

Steps for Solving Linear Equation

Variable n cannot be equal to -3 since division by zero is not defined. Multiply both sides of the equation by n+3.

$$x\left(n+3\right)=40n+2$$

Use the distributive property to multiply x by n+3.

$$xn+3x=40n+2$$

Subtract 40n from both sides.

$$xn+3x-40n=2$$

Subtract 3x from both sides.

$$xn-40n=2-3x$$

Combine all terms containing n.

$$\left(x-40\right)n=2-3x$$

Divide both sides by x-40.

$$\frac{\left(x-40\right)n}{x-40}=\frac{2-3x}{x-40}$$

Dividing by x-40 undoes the multiplication by x-40.

$$n=\frac{2-3x}{x-40}$$

Variable n cannot be equal to -3.

$$n=\frac{2-3x}{x-40}\text{, }n\neq -3$$

Solve for x

$$x=\frac{2\left(20n+1\right)}{n+3}$$

$$n\neq -3$$