Solve x=3-2y/-4

$$x= \frac{ 3-2y }{ -4 }$$

Solve for x

$$x=\frac{y}{2}-\frac{3}{4}$$

Solution Steps

Multiply both numerator and denominator by -1.

$$x=\frac{-3+2y}{4}$$

Divide each term of -3+2y by 4 to get -\frac{3}{4}+\frac{1}{2}y.

$$x=-\frac{3}{4}+\frac{1}{2}y$$

Solve for y

$$y=2x+\frac{3}{2}$$

Steps for Solving Linear Equation

Multiply both numerator and denominator by -1.

$$x=\frac{-3+2y}{4}$$

Divide each term of -3+2y by 4 to get -\frac{3}{4}+\frac{1}{2}y.

$$x=-\frac{3}{4}+\frac{1}{2}y$$

Swap sides so that all variable terms are on the left hand side.

$$-\frac{3}{4}+\frac{1}{2}y=x$$

Add \frac{3}{4} to both sides.

$$\frac{1}{2}y=x+\frac{3}{4}$$

Multiply both sides by 2.

$$\frac{\frac{1}{2}y}{\frac{1}{2}}=\frac{x+\frac{3}{4}}{\frac{1}{2}}$$

Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.

$$y=\frac{x+\frac{3}{4}}{\frac{1}{2}}$$

Divide x+\frac{3}{4} by \frac{1}{2} by multiplying x+\frac{3}{4} by the reciprocal of \frac{1}{2}.

$$y=2x+\frac{3}{2}$$