Solve x=10-3y/8y

$$x= \frac{ 10-3y }{ 8y }$$

Solve for y

$$y=\frac{10}{8x+3}$$

$$x\neq -\frac{3}{8}$$

Steps for Solving Linear Equation

Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 8y.

$$x\times 8y=10-3y$$

Add 3y to both sides.

$$x\times 8y+3y=10$$

Combine all terms containing y.

$$\left(x\times 8+3\right)y=10$$

The equation is in standard form.

$$\left(8x+3\right)y=10$$

Divide both sides by 8x+3.

$$\frac{\left(8x+3\right)y}{8x+3}=\frac{10}{8x+3}$$

Dividing by 8x+3 undoes the multiplication by 8x+3.

$$y=\frac{10}{8x+3}$$

Variable y cannot be equal to 0.

$$y=\frac{10}{8x+3}\text{, }y\neq 0$$

Solve for x

$$x=-\frac{3}{8}+\frac{5}{4y}$$

$$y\neq 0$$