Solve x=-8y/-12y-6

$$x= \frac{ -8y }{ -12y-6 }$$

Solve for y

$$y=\frac{3x}{2\left(2-3x\right)}$$

$$x\neq \frac{2}{3}$$

Steps for Solving Linear Equation

Variable y cannot be equal to -\frac{1}{2} since division by zero is not defined. Multiply both sides of the equation by 6\left(-2y-1\right).

$$x\times 6\left(-2y-1\right)=-8y$$

Use the distributive property to multiply x\times 6 by -2y-1.

$$-12xy-x\times 6=-8y$$

Multiply -1 and 6 to get -6.

$$-12xy-6x=-8y$$

Add 8y to both sides.

$$-12xy-6x+8y=0$$

Add 6x to both sides. Anything plus zero gives itself.

$$-12xy+8y=6x$$

Combine all terms containing y.

$$\left(-12x+8\right)y=6x$$

The equation is in standard form.

$$\left(8-12x\right)y=6x$$

Divide both sides by -12x+8.

$$\frac{\left(8-12x\right)y}{8-12x}=\frac{6x}{8-12x}$$

Dividing by -12x+8 undoes the multiplication by -12x+8.

$$y=\frac{6x}{8-12x}$$

Divide 6x by -12x+8.

$$y=\frac{3x}{2\left(2-3x\right)}$$

Variable y cannot be equal to -\frac{1}{2}.

$$y=\frac{3x}{2\left(2-3x\right)}\text{, }y\neq -\frac{1}{2}$$

Solve for x

$$x=\frac{4y}{3\left(2y+1\right)}$$

$$y\neq -\frac{1}{2}$$