Solve x=frac{sqrt{y}}{2}-1

$$x= \frac{ \sqrt{ y } }{ 2 } -1$$

Solve for y

$$y=4\left(x+1\right)^{2}$$

$$2x+2\geq 0$$

Steps for Solving Radical Equations

Swap sides so that all variable terms are on the left hand side.

$$\frac{\sqrt{y}}{2}-1=x$$

Add 1 to both sides.

$$\frac{\sqrt{y}}{2}=x+1$$

Multiply both sides of the equation by 2.

$$\sqrt{y}=2x+2$$

Square both sides of the equation.

$$y=4\left(x+1\right)^{2}$$

Solve for x (complex solution)

$$x=\frac{\sqrt{y}-2}{2}$$

Solve for y (complex solution)

$$y=4\left(x+1\right)^{2}$$

$$x=-1\text{ or }arg(2x+2)<\pi$$

Solve for x

$$x=\frac{\sqrt{y}-2}{2}$$

$$y\geq 0$$