Solve for y
y=45x^{2}
x\geq 0
Solve for y (complex solution)
y=45x^{2}
arg(x)<\pi \text{ or }x=0
Solve for x
x=\frac{\sqrt{5y}}{15}
y\geq 0
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\frac{\sqrt{5y}}{15}=x
Swap sides so that all variable terms are on the left hand side.
\frac{\frac{1}{15}\sqrt{5y}}{\frac{1}{15}}=\frac{x}{\frac{1}{15}}
Multiply both sides by 15.
\sqrt{5y}=\frac{x}{\frac{1}{15}}
Dividing by \frac{1}{15} undoes the multiplication by \frac{1}{15}.
\sqrt{5y}=15x
Divide x by \frac{1}{15} by multiplying x by the reciprocal of \frac{1}{15}.
5y=225x^{2}
Square both sides of the equation.
\frac{5y}{5}=\frac{225x^{2}}{5}
Divide both sides by 5.
y=\frac{225x^{2}}{5}
Dividing by 5 undoes the multiplication by 5.
y=45x^{2}
Divide 225x^{2} by 5.
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