Solve x+y-z=z+y-x+40

$$x+y-z=z+y-x+40$$

Solve for x

$$x=z+20$$

Steps for Solving Linear Equation

Add x to both sides.

$$x+y-z+x=z+y+40$$

Combine x and x to get 2x.

$$2x+y-z=z+y+40$$

Subtract y from both sides.

$$2x-z=z+y+40-y$$

Combine y and -y to get 0.

$$2x-z=z+40$$

Add z to both sides.

$$2x=z+40+z$$

Combine z and z to get 2z.

$$2x=2z+40$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{2z+40}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{2z+40}{2}$$

Divide 40+2z by 2.

$$x=z+20$$

Solve for y (complex solution)

$$y\in \mathrm{C}$$

$$x=z+20$$

Solve for y

$$y\in \mathrm{R}$$

$$x=z+20$$