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Solve for x (complex solution)
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3x+3y=-x^{2}-2x+15
Multiply both sides of the equation by 3.
3y=-x^{2}-2x+15-3x
Subtract 3x from both sides.
3y=-x^{2}-5x+15
Combine -2x and -3x to get -5x.
3y=15-5x-x^{2}
The equation is in standard form.
\frac{3y}{3}=\frac{15-5x-x^{2}}{3}
Divide both sides by 3.
y=\frac{15-5x-x^{2}}{3}
Dividing by 3 undoes the multiplication by 3.
y=-\frac{x^{2}}{3}-\frac{5x}{3}+5
Divide -x^{2}-5x+15 by 3.