Solve x+8leq3x+1

$$x+8 \leq 3x+1$$

Solve for x

$$x\geq \frac{7}{2}$$

Solution Steps

Subtract 3x from both sides.

$$x+8-3x\leq 1$$

Combine x and -3x to get -2x.

$$-2x+8\leq 1$$

Subtract 8 from both sides.

$$-2x\leq 1-8$$

Subtract 8 from 1 to get -7.

$$-2x\leq -7$$

Divide both sides by -2. Since -2 is negative, the inequality direction is changed.

$$x\geq \frac{-7}{-2}$$

Fraction \frac{-7}{-2} can be simplified to \frac{7}{2} by removing the negative sign from both the numerator and the denominator.

$$x\geq \frac{7}{2}$$