Solve x+4+8x+10=

$$x+4+8x+10 =$$

Evaluate

$$9x+14$$

Solution Steps

Combine x and 8x to get 9x.

$$9x+4+10$$

Add 4 and 10 to get 14.

$$9x+14$$

Differentiate w.r.t. x

$$9$$

Steps Using Derivative Rule for Sum

Combine x and 8x to get 9x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(9x+4+10)$$

Add 4 and 10 to get 14.

$$\frac{\mathrm{d}}{\mathrm{d}x}(9x+14)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$9x^{1-1}$$

Subtract 1 from 1.

$$9x^{0}$$

For any term t except 0, t^{0}=1.

$$9\times 1$$

For any term t, t\times 1=t and 1t=t.

$$9$$