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\left(1+3y\right)x=-11
Combine all terms containing x.
\left(3y+1\right)x=-11
The equation is in standard form.
\frac{\left(3y+1\right)x}{3y+1}=-\frac{11}{3y+1}
Divide both sides by 1+3y.
x=-\frac{11}{3y+1}
Dividing by 1+3y undoes the multiplication by 1+3y.
3yx=-11-x
Subtract x from both sides.
3xy=-x-11
The equation is in standard form.
\frac{3xy}{3x}=\frac{-x-11}{3x}
Divide both sides by 3x.
y=\frac{-x-11}{3x}
Dividing by 3x undoes the multiplication by 3x.
y=-\frac{1}{3}-\frac{11}{3x}
Divide -11-x by 3x.