Solve x+3=yx*2

$$x+3=yx \times 2$$

Solve for x

$$x=-\frac{3}{1-2y}$$

$$y\neq \frac{1}{2}$$

Steps for Solving Linear Equation

Subtract yx\times 2 from both sides.

$$x+3-yx\times 2=0$$

Multiply -1 and 2 to get -2.

$$x+3-2yx=0$$

Subtract 3 from both sides. Anything subtracted from zero gives its negation.

$$x-2yx=-3$$

Combine all terms containing x.

$$\left(1-2y\right)x=-3$$

Divide both sides by 1-2y.

$$\frac{\left(1-2y\right)x}{1-2y}=-\frac{3}{1-2y}$$

Dividing by 1-2y undoes the multiplication by 1-2y.

$$x=-\frac{3}{1-2y}$$

Solve for y

$$y=\frac{1}{2}+\frac{3}{2x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$yx\times 2=x+3$$

The equation is in standard form.

$$2xy=x+3$$

Divide both sides by 2x.

$$\frac{2xy}{2x}=\frac{x+3}{2x}$$

Dividing by 2x undoes the multiplication by 2x.

$$y=\frac{x+3}{2x}$$

Divide x+3 by 2x.

$$y=\frac{1}{2}+\frac{3}{2x}$$