Solve x+3divx^4-9x^2+x+3

$$x+3 \div { x }^{ 4 } -9 { x }^{ 2 } +x+3$$

Evaluate

$$-9x^{2}+2x+3+\frac{3}{x^{4}}$$

Short Solution Steps

Combine x and x to get 2x.

$$2x+\frac{3}{x^{4}}-9x^{2}+3$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 2x-9x^{2}+3 times \frac{x^{4}}{x^{4}}.

$$\frac{\left(2x-9x^{2}+3\right)x^{4}}{x^{4}}+\frac{3}{x^{4}}$$

Since \frac{\left(2x-9x^{2}+3\right)x^{4}}{x^{4}} and \frac{3}{x^{4}} have the same denominator, add them by adding their numerators.

$$\frac{\left(2x-9x^{2}+3\right)x^{4}+3}{x^{4}}$$

Do the multiplications in \left(2x-9x^{2}+3\right)x^{4}+3.

$$\frac{2x^{5}-9x^{6}+3x^{4}+3}{x^{4}}$$

Factor

$$-\frac{9x^{6}-2x^{5}-3x^{4}-3}{x^{4}}$$