Solve for x
x=-2y+3z-4
Solve for y
y=\frac{3z}{2}-\frac{x}{2}-2
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x-3z=-4-2y
Subtract 2y from both sides.
x=-4-2y+3z
Add 3z to both sides.
2y-3z=-4-x
Subtract x from both sides.
2y=-4-x+3z
Add 3z to both sides.
2y=-x+3z-4
The equation is in standard form.
\frac{2y}{2}=\frac{-x+3z-4}{2}
Divide both sides by 2.
y=\frac{-x+3z-4}{2}
Dividing by 2 undoes the multiplication by 2.
y=\frac{3z}{2}-\frac{x}{2}-2
Divide -4-x+3z by 2.
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