Solve x+2y-2z=x-2(z+y)

$$x+2y-2z=x-2(z+y)$$

Solve for y

$$y=0$$

Steps for Solving Linear Equation

Use the distributive property to multiply -2 by z+y.

$$x+2y-2z=x-2z-2y$$

Add 2y to both sides.

$$x+2y-2z+2y=x-2z$$

Combine 2y and 2y to get 4y.

$$x+4y-2z=x-2z$$

Subtract x from both sides.

$$4y-2z=x-2z-x$$

Combine x and -x to get 0.

$$4y-2z=-2z$$

Add 2z to both sides.

$$4y=-2z+2z$$

Combine -2z and 2z to get 0.

$$4y=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since 4 is not equal to 0, y must be equal to 0.

$$y=0$$

Solve for x

$$x\in \mathrm{R}$$

$$y=0$$