Solve for x
x=2-3z-2y
Solve for y
y=-\frac{x}{2}-\frac{3z}{2}+1
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x+3z=2-2y
Subtract 2y from both sides.
x=2-2y-3z
Subtract 3z from both sides.
2y+3z=2-x
Subtract x from both sides.
2y=2-x-3z
Subtract 3z from both sides.
2y=2-3z-x
The equation is in standard form.
\frac{2y}{2}=\frac{2-3z-x}{2}
Divide both sides by 2.
y=\frac{2-3z-x}{2}
Dividing by 2 undoes the multiplication by 2.
y=-\frac{x}{2}-\frac{3z}{2}+1
Divide 2-x-3z by 2.
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