Solve for x
x=\frac{7}{2y+1}
y\neq -\frac{1}{2}
Solve for y
y=-\frac{1}{2}+\frac{7}{2x}
x\neq 0
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\left(1+2y\right)x=7
Combine all terms containing x.
\left(2y+1\right)x=7
The equation is in standard form.
\frac{\left(2y+1\right)x}{2y+1}=\frac{7}{2y+1}
Divide both sides by 1+2y.
x=\frac{7}{2y+1}
Dividing by 1+2y undoes the multiplication by 1+2y.
2xy=7-x
Subtract x from both sides.
\frac{2xy}{2x}=\frac{7-x}{2x}
Divide both sides by 2x.
y=\frac{7-x}{2x}
Dividing by 2x undoes the multiplication by 2x.
y=-\frac{1}{2}+\frac{7}{2x}
Divide 7-x by 2x.
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