Solve x+(x+1)-1/3=6

$$x+(x+1)- \frac{ 1 }{ 3 } =6$$

Solve for x

$$x = \frac{8}{3} = 2\frac{2}{3} \approx 2.666666667$$

Steps for Solving Linear Equation

Combine x and x to get 2x.

$$2x+1-\frac{1}{3}=6$$

Convert 1 to fraction \frac{3}{3}.

$$2x+\frac{3}{3}-\frac{1}{3}=6$$

Since \frac{3}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$2x+\frac{3-1}{3}=6$$

Subtract 1 from 3 to get 2.

$$2x+\frac{2}{3}=6$$

Subtract \frac{2}{3} from both sides.

$$2x=6-\frac{2}{3}$$

Convert 6 to fraction \frac{18}{3}.

$$2x=\frac{18}{3}-\frac{2}{3}$$

Since \frac{18}{3} and \frac{2}{3} have the same denominator, subtract them by subtracting their numerators.

$$2x=\frac{18-2}{3}$$

Subtract 2 from 18 to get 16.

$$2x=\frac{16}{3}$$

Divide both sides by 2.

$$x=\frac{\frac{16}{3}}{2}$$

Express \frac{\frac{16}{3}}{2} as a single fraction.

$$x=\frac{16}{3\times 2}$$

Multiply 3 and 2 to get 6.

$$x=\frac{16}{6}$$

Reduce the fraction \frac{16}{6} to lowest terms by extracting and canceling out 2.

$$x=\frac{8}{3}$$