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x+\frac{1}{3}=1^{2}
Rewrite the square root of the division \frac{1}{9} as the division of square roots \frac{\sqrt{1}}{\sqrt{9}}. Take the square root of both numerator and denominator.
x+\frac{1}{3}=1
Calculate 1 to the power of 2 and get 1.
x=1-\frac{1}{3}
Subtract \frac{1}{3} from both sides.
x=\frac{3}{3}-\frac{1}{3}
Convert 1 to fraction \frac{3}{3}.
x=\frac{3-1}{3}
Since \frac{3}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.
x=\frac{2}{3}
Subtract 1 from 3 to get 2.