Solve x+x^2/2+x^3/6+x^2/2

$$x+ \frac{ { x }^{ 2 } }{ 2 } + \frac{ { x }^{ 3 } }{ 6 } + \frac{ { x }^{ 2 } }{ 2 }$$

Evaluate

$$\frac{x^{3}}{6}+x^{2}+x$$

Short Solution Steps

Combine \frac{x^{2}}{2} and \frac{x^{2}}{2} to get x^{2}.

$$x+x^{2}+\frac{x^{3}}{6}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply x+x^{2} times \frac{6}{6}.

$$\frac{6\left(x+x^{2}\right)}{6}+\frac{x^{3}}{6}$$

Since \frac{6\left(x+x^{2}\right)}{6} and \frac{x^{3}}{6} have the same denominator, add them by adding their numerators.

$$\frac{6\left(x+x^{2}\right)+x^{3}}{6}$$

Do the multiplications in 6\left(x+x^{2}\right)+x^{3}.

$$\frac{6x+6x^{2}+x^{3}}{6}$$

Factor

$$\frac{x\left(x-\left(-\sqrt{3}-3\right)\right)\left(x-\left(\sqrt{3}-3\right)\right)}{6}$$