Solve x+1/31/2x=1/3x-5

$$x+ \frac{ 1 }{ 3 } \frac { 1 } { 2 } x= \frac{ 1 }{ 3 } x-5$$

Solve for x

$$x=-6$$

Steps for Solving Linear Equation

Multiply \frac{1}{3} times \frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$x+\frac{1\times 1}{3\times 2}x=\frac{1}{3}x-5$$

Do the multiplications in the fraction \frac{1\times 1}{3\times 2}.

$$x+\frac{1}{6}x=\frac{1}{3}x-5$$

Combine x and \frac{1}{6}x to get \frac{7}{6}x.

$$\frac{7}{6}x=\frac{1}{3}x-5$$

Subtract \frac{1}{3}x from both sides.

$$\frac{7}{6}x-\frac{1}{3}x=-5$$

Combine \frac{7}{6}x and -\frac{1}{3}x to get \frac{5}{6}x.

$$\frac{5}{6}x=-5$$

Multiply both sides by \frac{6}{5}, the reciprocal of \frac{5}{6}.

$$x=-5\times \frac{6}{5}$$

Multiply -5 times \frac{6}{5}.

$$x=-6$$