Solve xz=5+xy

$$x z = 5 + x y$$

Solve for x

$$x=\frac{5}{z-y}$$

$$z\neq y$$

Steps for Solving Linear Equation

Subtract xy from both sides.

$$xz-xy=5$$

Combine all terms containing x.

$$\left(z-y\right)x=5$$

Divide both sides by -y+z.

$$\frac{\left(z-y\right)x}{z-y}=\frac{5}{z-y}$$

Dividing by -y+z undoes the multiplication by -y+z.

$$x=\frac{5}{z-y}$$

Solve for y

$$y=z-\frac{5}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$5+xy=xz$$

Subtract 5 from both sides.

$$xy=xz-5$$

Divide both sides by x.

$$\frac{xy}{x}=\frac{xz-5}{x}$$

Dividing by x undoes the multiplication by x.

$$y=\frac{xz-5}{x}$$

Divide xz-5 by x.

$$y=z-\frac{5}{x}$$