Solve for x
x=-\frac{y-8}{y-1}
y\neq 1
Solve for y
y=\frac{x+8}{x+1}
x\neq -1
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\left(y-1\right)x=8-y
Combine all terms containing x.
\frac{\left(y-1\right)x}{y-1}=\frac{8-y}{y-1}
Divide both sides by y-1.
x=\frac{8-y}{y-1}
Dividing by y-1 undoes the multiplication by y-1.
xy-x+y=8
Add y to both sides.
xy+y=8+x
Add x to both sides.
\left(x+1\right)y=8+x
Combine all terms containing y.
\left(x+1\right)y=x+8
The equation is in standard form.
\frac{\left(x+1\right)y}{x+1}=\frac{x+8}{x+1}
Divide both sides by x+1.
y=\frac{x+8}{x+1}
Dividing by x+1 undoes the multiplication by x+1.
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