Solve xy-2y-12=0

$$x y - 2 y - 12 = 0$$

Solve for x

$$x=2+\frac{12}{y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Add 2y to both sides. Anything plus zero gives itself.

$$xy-12=2y$$

Add 12 to both sides.

$$xy=2y+12$$

The equation is in standard form.

$$yx=2y+12$$

Divide both sides by y.

$$\frac{yx}{y}=\frac{2y+12}{y}$$

Dividing by y undoes the multiplication by y.

$$x=\frac{2y+12}{y}$$

Divide 12+2y by y.

$$x=2+\frac{12}{y}$$

Solve for y

$$y=\frac{12}{x-2}$$

$$x\neq 2$$

Steps for Solving Linear Equation

Add 12 to both sides. Anything plus zero gives itself.

$$xy-2y=12$$

Combine all terms containing y.

$$\left(x-2\right)y=12$$

Divide both sides by x-2.

$$\frac{\left(x-2\right)y}{x-2}=\frac{12}{x-2}$$

Dividing by x-2 undoes the multiplication by x-2.

$$y=\frac{12}{x-2}$$