Solve for x
x=\frac{17}{y-7}
y\neq 7
Solve for y
y=7+\frac{17}{x}
x\neq 0
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xy-17-7x=0
Subtract 7x from both sides.
xy-7x=17
Add 17 to both sides. Anything plus zero gives itself.
\left(y-7\right)x=17
Combine all terms containing x.
\frac{\left(y-7\right)x}{y-7}=\frac{17}{y-7}
Divide both sides by y-7.
x=\frac{17}{y-7}
Dividing by y-7 undoes the multiplication by y-7.
xy=7x+17
Add 17 to both sides.
\frac{xy}{x}=\frac{7x+17}{x}
Divide both sides by x.
y=\frac{7x+17}{x}
Dividing by x undoes the multiplication by x.
y=7+\frac{17}{x}
Divide 7x+17 by x.
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