Solve xyquadx+5=9

$$x y \quad x + 5 = 9$$

Solve for y

$$y=\frac{4}{x^{2}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply x and x to get x^{2}.

$$x^{2}y+5=9$$

Subtract 5 from both sides.

$$x^{2}y=9-5$$

Subtract 5 from 9 to get 4.

$$x^{2}y=4$$

Divide both sides by x^{2}.

$$\frac{x^{2}y}{x^{2}}=\frac{4}{x^{2}}$$

Dividing by x^{2} undoes the multiplication by x^{2}.

$$y=\frac{4}{x^{2}}$$

Solve for x (complex solution)

$$x=-2y^{-\frac{1}{2}}$$

$$x=2y^{-\frac{1}{2}}\text{, }y\neq 0$$

Solve for x

$$x=\frac{2}{\sqrt{y}}$$

$$x=-\frac{2}{\sqrt{y}}\text{, }y>0$$