Solve for x (complex solution)
\left\{\begin{matrix}\\x=8\text{, }&\text{unconditionally}\\x\in \mathrm{C}\text{, }&y=0\end{matrix}\right.
Solve for y (complex solution)
\left\{\begin{matrix}\\y=0\text{, }&\text{unconditionally}\\y\in \mathrm{C}\text{, }&x=8\end{matrix}\right.
Solve for x
\left\{\begin{matrix}\\x=8\text{, }&\text{unconditionally}\\x\in \mathrm{R}\text{, }&y=0\end{matrix}\right.
Solve for y
\left\{\begin{matrix}\\y=0\text{, }&\text{unconditionally}\\y\in \mathrm{R}\text{, }&x=8\end{matrix}\right.
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y^{2}x=8y^{2}
The equation is in standard form.
\frac{y^{2}x}{y^{2}}=\frac{8y^{2}}{y^{2}}
Divide both sides by y^{2}.
x=\frac{8y^{2}}{y^{2}}
Dividing by y^{2} undoes the multiplication by y^{2}.
x=8
Divide 8y^{2} by y^{2}.
xy^{2}-8y^{2}=0
Subtract 8y^{2} from both sides.
\left(x-8\right)y^{2}=0
Combine all terms containing y.
y^{2}=\frac{0}{x-8}
Dividing by -8+x undoes the multiplication by -8+x.
y^{2}=0
Divide 0 by -8+x.
y=0 y=0
Take the square root of both sides of the equation.
y=0
The equation is now solved. Solutions are the same.
xy^{2}-8y^{2}=0
Subtract 8y^{2} from both sides.
\left(x-8\right)y^{2}=0
Combine all terms containing y.
y=\frac{0±\sqrt{0^{2}}}{2\left(x-8\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -8+x for a, 0 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
y=\frac{0±0}{2\left(x-8\right)}
Take the square root of 0^{2}.
y=\frac{0}{2x-16}
Multiply 2 times -8+x.
y=0
Divide 0 by -16+2x.
y^{2}x=8y^{2}
The equation is in standard form.
\frac{y^{2}x}{y^{2}}=\frac{8y^{2}}{y^{2}}
Divide both sides by y^{2}.
x=\frac{8y^{2}}{y^{2}}
Dividing by y^{2} undoes the multiplication by y^{2}.
x=8
Divide 8y^{2} by y^{2}.
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