Solve for x
x=-\frac{4}{y-3}
y\neq 3
Solve for y
y=3-\frac{4}{x}
x\neq 0
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xy-3x=-4
Subtract 3x from both sides.
\left(y-3\right)x=-4
Combine all terms containing x.
\frac{\left(y-3\right)x}{y-3}=-\frac{4}{y-3}
Divide both sides by y-3.
x=-\frac{4}{y-3}
Dividing by y-3 undoes the multiplication by y-3.
xy=3x-4
The equation is in standard form.
\frac{xy}{x}=\frac{3x-4}{x}
Divide both sides by x.
y=\frac{3x-4}{x}
Dividing by x undoes the multiplication by x.
y=3-\frac{4}{x}
Divide 3x-4 by x.
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