Solve xy+y^2=2

$$x y + y ^ { 2 } = 2$$

Solve for x

$$x=-y+\frac{2}{y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Subtract y^{2} from both sides.

$$xy=2-y^{2}$$

The equation is in standard form.

$$yx=2-y^{2}$$

Divide both sides by y.

$$\frac{yx}{y}=\frac{2-y^{2}}{y}$$

Dividing by y undoes the multiplication by y.

$$x=\frac{2-y^{2}}{y}$$

Divide 2-y^{2} by y.

$$x=-y+\frac{2}{y}$$

Solve for y

$$y=\frac{\sqrt{x^{2}+8}-x}{2}$$

$$y=\frac{-\sqrt{x^{2}+8}-x}{2}$$