Solve xa+5(a+2b)=124

$$x a + 5 ( a + 2 b ) = 124$$

Solve for a (complex solution)

$$\left\{\begin{matrix}a=-\frac{2\left(5b-62\right)}{x+5}\text{, }&x\neq -5\\a\in \mathrm{C}\text{, }&b=\frac{62}{5}\text{ and }x=-5\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply 5 by a+2b.

$$xa+5a+10b=124$$

Subtract 10b from both sides.

$$xa+5a=124-10b$$

Combine all terms containing a.

$$\left(x+5\right)a=124-10b$$

Divide both sides by x+5.

$$\frac{\left(x+5\right)a}{x+5}=\frac{124-10b}{x+5}$$

Dividing by x+5 undoes the multiplication by x+5.

$$a=\frac{124-10b}{x+5}$$

Divide 124-10b by x+5.

$$a=\frac{2\left(62-5b\right)}{x+5}$$

Solve for a

$$\left\{\begin{matrix}a=-\frac{2\left(5b-62\right)}{x+5}\text{, }&x\neq -5\\a\in \mathrm{R}\text{, }&b=\frac{62}{5}\text{ and }x=-5\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply 5 by a+2b.

$$xa+5a+10b=124$$

Subtract 10b from both sides.

$$xa+5a=124-10b$$

Combine all terms containing a.

$$\left(x+5\right)a=124-10b$$

Divide both sides by x+5.

$$\frac{\left(x+5\right)a}{x+5}=\frac{124-10b}{x+5}$$

Dividing by x+5 undoes the multiplication by x+5.

$$a=\frac{124-10b}{x+5}$$

Divide 124-10b by x+5.

$$a=\frac{2\left(62-5b\right)}{x+5}$$

Solve for b

$$b=-\frac{ax}{10}-\frac{a}{2}+\frac{62}{5}$$

Steps for Solving Linear Equation

Use the distributive property to multiply 5 by a+2b.

$$xa+5a+10b=124$$

Subtract xa from both sides.

$$5a+10b=124-xa$$

Subtract 5a from both sides.

$$10b=124-xa-5a$$

The equation is in standard form.

$$10b=124-5a-ax$$

Divide both sides by 10.

$$\frac{10b}{10}=\frac{124-5a-ax}{10}$$

Dividing by 10 undoes the multiplication by 10.

$$b=\frac{124-5a-ax}{10}$$

Divide 124-xa-5a by 10.

$$b=-\frac{ax}{10}-\frac{a}{2}+\frac{62}{5}$$