Solve x_{r}=2+1/3(-4)/1+frac{1{3}}

$$x _ { r } = \frac { 2 + \frac { 1 } { 3 } ( - 4 ) } { 1 + \frac { 1 } { 3 } }$$

Solve for x_r

$$x_{r}=\frac{1}{2}=0.5$$

Steps for Solving Linear Equation

Multiply \frac{1}{3} and -4 to get \frac{-4}{3}.

$$x_{r}=\frac{2+\frac{-4}{3}}{1+\frac{1}{3}}$$

Fraction \frac{-4}{3} can be rewritten as -\frac{4}{3} by extracting the negative sign.

$$x_{r}=\frac{2-\frac{4}{3}}{1+\frac{1}{3}}$$

Convert 2 to fraction \frac{6}{3}.

$$x_{r}=\frac{\frac{6}{3}-\frac{4}{3}}{1+\frac{1}{3}}$$

Since \frac{6}{3} and \frac{4}{3} have the same denominator, subtract them by subtracting their numerators.

$$x_{r}=\frac{\frac{6-4}{3}}{1+\frac{1}{3}}$$

Subtract 4 from 6 to get 2.

$$x_{r}=\frac{\frac{2}{3}}{1+\frac{1}{3}}$$

Convert 1 to fraction \frac{3}{3}.

$$x_{r}=\frac{\frac{2}{3}}{\frac{3}{3}+\frac{1}{3}}$$

Since \frac{3}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$x_{r}=\frac{\frac{2}{3}}{\frac{3+1}{3}}$$

Add 3 and 1 to get 4.

$$x_{r}=\frac{\frac{2}{3}}{\frac{4}{3}}$$

Divide \frac{2}{3} by \frac{4}{3} by multiplying \frac{2}{3} by the reciprocal of \frac{4}{3}.

$$x_{r}=\frac{2}{3}\times \frac{3}{4}$$

Multiply \frac{2}{3} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$x_{r}=\frac{2\times 3}{3\times 4}$$

Cancel out 3 in both numerator and denominator.

$$x_{r}=\frac{2}{4}$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$x_{r}=\frac{1}{2}$$

Assign x_r

$$x_{r}≔\frac{1}{2}$$