Solve x_2^2-4x+3=0

$$x _ { 2 } ^ { 2 } - 4 x + 3 = 0$$

Solve for x

$$x=\frac{x_{2}^{2}+3}{4}$$

Steps for Solving Linear Equation

Subtract x_{2}^{2} from both sides. Anything subtracted from zero gives its negation.

$$-4x+3=-x_{2}^{2}$$

Subtract 3 from both sides.

$$-4x=-x_{2}^{2}-3$$

Divide both sides by -4.

$$\frac{-4x}{-4}=\frac{-x_{2}^{2}-3}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$x=\frac{-x_{2}^{2}-3}{-4}$$

Divide -x_{2}^{2}-3 by -4.

$$x=\frac{x_{2}^{2}+3}{4}$$

Solve for x_2 (complex solution)

$$x_{2}=-\sqrt{4x-3}$$

$$x_{2}=\sqrt{4x-3}$$

Solve for x_2

$$x_{2}=\sqrt{4x-3}$$

$$x_{2}=-\sqrt{4x-3}\text{, }x\geq \frac{3}{4}$$