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Solve for x_2
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x_{1}=\frac{94}{7}+\frac{8}{7}x_{2}
Divide each term of 94+8x_{2} by 7 to get \frac{94}{7}+\frac{8}{7}x_{2}.
\frac{94}{7}+\frac{8}{7}x_{2}=x_{1}
Swap sides so that all variable terms are on the left hand side.
\frac{8}{7}x_{2}=x_{1}-\frac{94}{7}
Subtract \frac{94}{7} from both sides.
\frac{\frac{8}{7}x_{2}}{\frac{8}{7}}=\frac{x_{1}-\frac{94}{7}}{\frac{8}{7}}
Divide both sides of the equation by \frac{8}{7}, which is the same as multiplying both sides by the reciprocal of the fraction.
x_{2}=\frac{x_{1}-\frac{94}{7}}{\frac{8}{7}}
Dividing by \frac{8}{7} undoes the multiplication by \frac{8}{7}.
x_{2}=\frac{7x_{1}}{8}-\frac{47}{4}
Divide x_{1}-\frac{94}{7} by \frac{8}{7} by multiplying x_{1}-\frac{94}{7} by the reciprocal of \frac{8}{7}.
x_{1}=\frac{94}{7}+\frac{8}{7}x_{2}
Divide each term of 94+8x_{2} by 7 to get \frac{94}{7}+\frac{8}{7}x_{2}.