Solve for x, y
x=-1
y=-2
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x=-1
Consider the second equation. Subtract 1 from both sides. Anything subtracted from zero gives its negation.
-1-y-1=0
Consider the first equation. Insert the known values of variables into the equation.
-2-y=0
Subtract 1 from -1 to get -2.
-y=2
Add 2 to both sides. Anything plus zero gives itself.
y=-2
Divide both sides by -1.
x=-1 y=-2
The system is now solved.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
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4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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