Solve x-y=0quad,quadx=4/3

$$x - y = 0 \quad , \quad x = \frac { 4 } { 3 }$$

Solve for x, y

$$x = \frac{4}{3} = 1\frac{1}{3} \approx 1.333333333$$

$$y = \frac{4}{3} = 1\frac{1}{3} \approx 1.333333333$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$\frac{4}{3}-y=0$$

Subtract \frac{4}{3} from both sides. Anything subtracted from zero gives its negation.

$$-y=-\frac{4}{3}$$

Divide both sides by -1.

$$y=\frac{-\frac{4}{3}}{-1}$$

Express \frac{-\frac{4}{3}}{-1} as a single fraction.

$$y=\frac{-4}{3\left(-1\right)}$$

Multiply 3 and -1 to get -3.

$$y=\frac{-4}{-3}$$

Fraction \frac{-4}{-3} can be simplified to \frac{4}{3} by removing the negative sign from both the numerator and the denominator.

$$y=\frac{4}{3}$$

The system is now solved.

$$x=\frac{4}{3} y=\frac{4}{3}$$