Solve for x
x=43
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x-7=\frac{3}{4}x+\frac{3}{4}\times 5
Use the distributive property to multiply \frac{3}{4} by x+5.
x-7=\frac{3}{4}x+\frac{3\times 5}{4}
Express \frac{3}{4}\times 5 as a single fraction.
x-7=\frac{3}{4}x+\frac{15}{4}
Multiply 3 and 5 to get 15.
x-7-\frac{3}{4}x=\frac{15}{4}
Subtract \frac{3}{4}x from both sides.
\frac{1}{4}x-7=\frac{15}{4}
Combine x and -\frac{3}{4}x to get \frac{1}{4}x.
\frac{1}{4}x=\frac{15}{4}+7
Add 7 to both sides.
\frac{1}{4}x=\frac{15}{4}+\frac{28}{4}
Convert 7 to fraction \frac{28}{4}.
\frac{1}{4}x=\frac{15+28}{4}
Since \frac{15}{4} and \frac{28}{4} have the same denominator, add them by adding their numerators.
\frac{1}{4}x=\frac{43}{4}
Add 15 and 28 to get 43.
x=\frac{43}{4}\times 4
Multiply both sides by 4, the reciprocal of \frac{1}{4}.
x=43
Cancel out 4 and 4.
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