Solve for x
x=4y+\frac{12}{5}
Solve for y
y=\frac{x}{4}-\frac{3}{5}
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5x-20y=2\times 5+2
Multiply both sides of the equation by 5.
5x-20y=10+2
Multiply 2 and 5 to get 10.
5x-20y=12
Add 10 and 2 to get 12.
5x=12+20y
Add 20y to both sides.
5x=20y+12
The equation is in standard form.
\frac{5x}{5}=\frac{20y+12}{5}
Divide both sides by 5.
x=\frac{20y+12}{5}
Dividing by 5 undoes the multiplication by 5.
x=4y+\frac{12}{5}
Divide 12+20y by 5.
5x-20y=2\times 5+2
Multiply both sides of the equation by 5.
5x-20y=10+2
Multiply 2 and 5 to get 10.
5x-20y=12
Add 10 and 2 to get 12.
-20y=12-5x
Subtract 5x from both sides.
\frac{-20y}{-20}=\frac{12-5x}{-20}
Divide both sides by -20.
y=\frac{12-5x}{-20}
Dividing by -20 undoes the multiplication by -20.
y=\frac{x}{4}-\frac{3}{5}
Divide 12-5x by -20.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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