Solve x-3y+12=0

$$x - 3 y + 12 = 0$$

Solve for x

$$x=3\left(y-4\right)$$

Solution Steps

Add 3y to both sides. Anything plus zero gives itself.

$$x+12=3y$$

Subtract 12 from both sides.

$$x=3y-12$$

Solve for y

$$y=\frac{x+12}{3}$$

Steps for Solving Linear Equation

Subtract x from both sides. Anything subtracted from zero gives its negation.

$$-3y+12=-x$$

Subtract 12 from both sides.

$$-3y=-x-12$$

Divide both sides by -3.

$$\frac{-3y}{-3}=\frac{-x-12}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$y=\frac{-x-12}{-3}$$

Divide -x-12 by -3.

$$y=\frac{x}{3}+4$$